One of the sharp corners of a right-angled triangle is 40 degrees larger than the other.

One of the sharp corners of a right-angled triangle is 40 degrees larger than the other. then what will the degree measures of these angles be equal to?

We draw up an equation in which we write one of the acute corners of a right-angled triangle as x °.

Since it is 40 ° larger than the second acute angle, then its value will be: x – 40 °.

Since the sum of all the angles of any triangle is 180 °, and the value of the right angle is 90 °, we get the following equation:

x + x – 40 + 90 = 180.

2 * x = 130.

x = 130/2 = 65 ° (first angle).

x – 40 = 65 – 40 = 25 ° (second angle).

Answer: The angles of the triangle are 25 °, 65 ° and 90 °.