One of the sharp corners of a right triangle is 2 times larger than the other. Find the sharp corners of the triangle.

1. In trigonometry, it is known that the sum of all the angles of a triangle is 180 °.

2. If, according to the problem statement, it is specified that the triangle is rectangular, then the sum of two acute angles is equal to 180 ° – 90 ° = 90 °.

Let’s designate the smaller acute angle as x, then the second 2 times larger is equal to 2 x.

Let’s write the equation and find the value of x.

x + 2 x = 90 °;

3x = 90 °;

x = 30 °.

The larger acute angle is 2 x = 2 * 30 ° = 60 °.

Answer: One acute angle of the triangle is 30 °, the other 60 °.

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