One of the sharp corners of a right triangle is 20 degrees larger than the other. Find all corners.

Let the angle BAC = X0, then, by condition, the angle ACB = (X + 20) 0.

The sum of the acute angles of a right-angled triangle is 90, then X + X + 20 = 90.

2 * X = 70.

X = BAC = 70/2 = 35.

Angle ACB = 35 + 20 = 55.

Answer: The angles of triangle ABC are 90, 55, 35.



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