One of the sides of an obtuse isosceles triangle is 17cm smaller than the other. Find the sides of this triangle

One of the sides of an obtuse isosceles triangle is 17cm smaller than the other. Find the sides of this triangle if its perimeter is 77cm.

Since the ABC triangle is obtuse-angled and isosceles, its base AC is greater than the length of the lateral sides.

Let AB = BC = X cm, then AC = X + 17 cm.

Ravs = 77 = X + X + 17 + X.

3 * X = 60.

AB = BC = X = 60/3 = 20 cm, AC = 20 + 17 = 37 cm.

Answer: The sides of the triangle are 20 cm, 20 cm, 37 cm.



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