One of the sides of the parallelogram is 6 cm larger than the other and its perimeter is 48 cm

One of the sides of the parallelogram is 6 cm larger than the other and its perimeter is 48 cm, find the sides of the parallelogram.

Let’s call this parallelogram ABCD, where AB = CD and BC = AD. Since it is said that one of the sides is 6 cm larger than the other, then we denote the length of the smaller side (AB) as x cm, then the length of the larger side (BC) is (x + 6) cm, we write down what the perimeter is equal to:
P = 2 (AB + BC) = 2 (x + x + 6) = 2 (2x + 6) = 48 cm.
2x + 6 = 24;
2x = 18;
x = 9.
The length of the smaller side is 9 cm, then the length of the larger side is:
9 + 6 = 15 cm.
Answer: the lengths of the sides of this parallelogram are in pairs equal to 9 and 15 cm, respectively.