One of the sides of the quadrangle is 8 centimeters, the second side is 3 times larger
One of the sides of the quadrangle is 8 centimeters, the second side is 3 times larger than the first and the third is 70 meters less than the second and 11 meters more than 4. Calculate the perimeter of the quadrangle.
Take the sides of the quadrangle as A, B, C, D.
It is known that A = 8 cm.
Hence:
B = 3 * A = 3 * 8 = 24 cm;
Now, knowing B, we find C, which is 7 cm less than the second.
C = B – 7 = 24 – 7 = 17 cm;
B is 11 cm more than G. Hence G is 11 cm less than C.
G = C – 11 = 17 – 11 = 6 cm.
So, the sides of the quadrilateral are:
A = 8 cm;
B = 24 cm;
C = 17 cm;
G = 6 cm;
Find the perimeter of the quadrangle by adding the lengths of all its sides.
We get:
P = A + B + C + G = 8 + 24 + 17 + 6 = 55 cm.
So, the perimeter of the quadrangle is 55 cm.
Answer: 55 cm.