One of the sides of the rectangle is 12 cm larger than the other. Find its sides and area if the perimeter is 64 cm.

1. Let’s take the first side of the rectangle as x cm.

2. Since its second side is 12 cm larger, therefore its length is (x + 12) cm.

3. Well, since we know that the perimeter of a given rectangle is 64 cm, then we can write an equation, calculating which we find out what the first side of this rectangle is equal to.

P = 64 = 2 * (x + x + 12);

64/2 = x + x + 2;

32 – 2 = 2x;

2x = 30;

x = 30/2;

x = 15 cm.

4. Find out what the length of the second side is.

15 + 12 = 27 cm.

5. Now let’s calculate the area of the rectangle.

S = 15 * 27 = 360 cm ^ 2.