One of the sides of the rectangle is 2 cm smaller than the other and half the size of the third

One of the sides of the rectangle is 2 cm smaller than the other and half the size of the third, find its sides if the perimeter is 22 cm.

Let’s say that the second side of the figure is x cm.

Since the first is 2 cm less than the second, its length will be: x – 2 cm.

In this case, the length of the third side will be: 2 * (x – 2).

Since the perimeter is equal to the sum of the sides of the figure, we get the equation:

x + x – 2 + 2 * x – 4 = 22.

4 * x = 22 + 6.

4 * x = 28.

x = 28/4 = 7 cm (second side).

x – 2 = 7 – 2 = 5 cm (first side).

2 * x – 4 = 2 * 7 – 4 = 14 – 4 = 10 cm.

Answer: The sides of the figure are 5, 7 and 10 centimeters.