One of the sides of the rectangle is 3 m larger than the other, and its area is 10 m2. What is the smaller side of the rectangle.

Let the smaller side of the rectangle be x meters, then the larger side of the rectangle is (x + 3) meters (if … more, then you need to add). The area of a rectangle is equal to the product of the lengths of its sides, i.e. x (x + 3) m ^ 2 or 10 m ^ 2. Let’s make an equation and solve it.
x (x + 3) = 10;
x ^ 2 + 3x = 10;
x ^ 2 + 3x – 10 = 0;
D = b ^ 2 – 4ac;
D = 3 ^ 2 – 4 * 1 * (-10) = 9 + 40 = 49; √D = √49 = 7;
x = (-b ± √D) / (2a);
x1 = (-3 + 7) / (2 * 1) = 4/2 = 2 (m) – the smaller side;
x2 = (-3 – 7) / 2 = -10/2 = -5 – side length cannot be negative.
Answer. 2 m.