One of the sides of the rectangle is 32cm, and it is 4 times larger than the other.

One of the sides of the rectangle is 32cm, and it is 4 times larger than the other. find the area and perimeter of the rectangle.

1. According to the problem statement, it is given that the length of one side of the rectangle is 32 cm, and the second is 4 times shorter.

Let’s calculate the value of the width.

32 cm: 4 = 8 cm.

2. In geometry there is a known formula for calculating the area S of a rectangle – it is equal to the product of length and width.

Define what is S of a given rectangle

S = 32 cm * 8 cm = 256 cm².

3. Let’s calculate the perimeter P according to the rule: the perimeter of a rectangle is equal to twice the sum of its sides.

P = 2 * (32 cm + 8 cm) = 80 cm.

Answer: The area is 256 cm², the perimeter is 80 cm.