One of the sides of the triangle has a length of 3 decimeters 6 cm and the other is twice as long

One of the sides of the triangle has a length of 3 decimeters 6 cm and the other is twice as long as the length of the third side is 4 decimeters 3 centimeters less than the sum of the lengths in the first two sides, find the perimeter of the triangle.

The perimeter of a triangle is equal to the sum of the lengths of all its sides. Find all side lengths. If one side is 3 dm 6 cm and the other is twice as long, then the other side is (3 dm 6 cm) * 2 = 6 dm 12 cm = 7 dm 2 cm.The length of the third side is 4 dm 3 cm less than the sum of the two first. Find the sum of the first two sides: 3 dm 6 cm + 7 dm 2 cm = 10 dm 8 cm. Find the length of the third side: 10 dm 8 cm-4 dm 3 cm = 6 dm 5 cm. Find the perimeter: 3 dm 6 cm + 7 dm 2 cm + 6 dm 5 cm = 16 dm 13 cm = 17 dm 3 cm.



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