One of the sides of the triangle is 2 times larger than the second side, and the second is 7 inches less than

One of the sides of the triangle is 2 times larger than the second side, and the second is 7 inches less than the thirds. Find the sides of a triangle if its perimeter is 99 inches.

Let’s solve this problem using the equation.

Let the length of the second side of the triangle be x decimeters, then the length of the first side is 2 * x decimeters, and the length of the third side is (x + 7) decimeters. We know that the perimeter of the triangle is 99 decimeters. Let’s make the equation:

x + 2 * x + x + 7 = 99;

x + 2 * x + x = 99 – 7;

x + 2 * x + x = 92;

x * (1 + 2 + 1) = 92;

x * 4 = 92;

x = 92: 4;

x = 23 decimeters – the length of the second side of the triangle;

23 * 2 = 46 decimeters – the length of the first side of the triangle;

23 + 7 = 30 decimetres – the length of the third side of the triangle.

Answer: 23 decimetres; 46 decimeters; 30 decimeters.