One of the sides of the triangle is 3 times smaller than the second and 23dm

One of the sides of the triangle is 3 times smaller than the second and 23dm less than thirds, find the sides of the triangle if its perimeter is 108dm.

1. Let the first side of the triangle be equal to c, then the second is equal to 3c, and the third is 23 + c. All together they amount to 108 dm, we make an equation, we find with:
s + 23 + s + 3s = 108,
5s = 108 – 23,
5s = 85 dm.
c = 85/5,
s = 17 dm.
2. Find the second and third sides:
Side No. 2 = 3 * 17 = 51 dm,
side No. 3 = 17 + 23 = 40 dm.
Answer: the sides of the triangle are 17, 51 and 40 in.