One side is 5 cm larger than the other, the perimeter is 22. Find the sides of an isosceles triangle.

Since an isosceles triangle is given, in triangle ABC side AB is equal to side BC.
Let’s denote the side AC for X, then the two remaining sides will be equal to X + 5. AB = BC = X + 5, AC = X. Knowing that the perimeter is the sum of all the sides of the triangle, we write the equation:
AB + BC + AC = 22
(X + 5) + (X + 5) + x = 22
x + 5 + x + 5 + x = 22
3x + 10 = 22
3x = 22-10
3x = 12
x = 12/3
x = 4
AB = BC = 4 + 5 = 9
AC = 4
Answer: 9.9.4