One side of a rectangle is 8 decimeters larger than the other. Find the area of a rectangle if its perimeter is 28 decimeters.

Let’s find the lengths of the sides of this rectangle.

Let’s denote by x the length of the shorter side of this rectangle.

According to the condition of the problem, one side of this rectangle is 8 decimeters larger than the other, therefore, the length of the longer side of this rectangle is x + 8 cm.

According to the condition of the problem, the perimeter of this rectangle is 28 dm, therefore, we can draw up the following equation:

2 * (x + 8 + x) = 28.

We solve this equation:

2 * (2x + 8) = 28;

4x + 16 = 28;

4x = 28 – 16;

4x = 12;

x = 12/4;

x = 3 dm.

Knowing the smaller side, we find the larger one:

x + 8 = 3 + 8 = 11 dm.

Let’s find the area of ​​this rectangle:

12 * 3 = 36 dm2.

Answer: the area of ​​this rectangle is 36 dm2.