One side of an isosceles triangle is 4 cm, find the other two sides if the perimeter of the triangle is 14 cm
We write the formula for the perimeter of an isosceles triangle
P = a + a + b = 2a + b,
where a is the lateral side of an isosceles triangle, b is the base.
In the problem statement, we are given the values of the side of the triangle and the perimeter, but it is not indicated which side is given: side or base.
This problem has 2 solutions. Let’s consider them.
The first solution to the problem.
We know the base of the triangle, b = 4 cm, and its perimeter, P = 14 cm.
Find the side:
a = (P – b) ÷ 2.
a = (14 – 4) ÷ 2 = 10 ÷ 2 = 5 cm.
Answer: the other two sides of the triangle are equal: 5 cm, 5 cm.
The second option for solving the problem.
We know the side of the triangle, a = 4 cm, and its perimeter, P = 14 cm.
This means that the second lateral side of an isosceles triangle is also 4 cm.
Find the base of the triangle:
b = P – 2a.
b = 14 – (2 × 4) = 14 – 8 = 6 cm.
Answer: the other two sides of the triangle are equal: 4 cm, 6 cm.