One side of the parallelogram is 18 and the other 12, and the sine of one of the angles

One side of the parallelogram is 18 and the other 12, and the sine of one of the angles is one-sixth (1/6). find the area of the parallelogram

The area of a parallelogram is found according to the law: the area of a parallelogram is equal to the product of the adjacent sides of the parallelogram by the sine of the angle between them.

Formula of the law: S = ab • sin α.

By condition:

a = 18; b = 12; sin α = 1/6.

We have: S = 12 • 18 • 1/6 = 12 • 3 = 36.

Note: the area of a triangle, as a half of a parallelogram, is found by analogy, S = 1/2 • ab • sin α.