One side of the rectangle is 2 cm larger than the other, and the area of the rectangle is 24 cm ^ 2.

One side of the rectangle is 2 cm larger than the other, and the area of the rectangle is 24 cm ^ 2. Find the perimeter of the rectangle.

Let us denote by variable x the length of less than their sides of the rectangle.

Therefore, the length of the larger side we can express through (x + 2).

Knowing that the area of this rectangle is 24 cm2, we draw up an equation and determine the lengths of its sides:

x * (x + 2) = 24;

x ^ 2 + 2x – 24 = 0;

D = 4 – 4 (-24) = 100 = 102;

x1 = (-2 + 10) / 2 = 4;

x2 = (-2 – 10) / 2 = -6.

4 + 2 = 6.

We determine the perimeter of the rectangle, knowing that it is equal to the sum of its measurements multiplied by two:

2 * (4 + 6) = 20.

Answer: The perimeter is 20 cm.