One side of the rectangle is 2 times larger than the other and its perimeter is 16 cm, which is equal

One side of the rectangle is 2 times larger than the other and its perimeter is 16 cm, which is equal to the large side of the rectangle.

Let’s denote the smaller side of this rectangle by x.

According to the condition of the problem, one side of this rectangle is 2 times larger than the other, therefore the length of the larger side of this rectangle is 2x.

According to the condition of the problem, the perimeter of this rectangle is 16 cm, therefore, we can draw up the following equation:

2 * (2x + x) = 16.

We solve the resulting equation:

2 * 3x = 16;

6x = 16;

x = 16/6;

x = 8/3 cm.

We find what the large side of this rectangle is equal to:

2x = (8/3) * 2 = 16/3 = 5 1/3 cm.

Answer: The large side of this rectangle is 5 1/3 cm.