One side of the rectangle is 4 cm larger than the other. Find the sides of a rectangle if its area is 45 cm2.

Let X be the side AB of rectangle ABCD. Then BC = X + 4 S = AB • BC 45 = X (X + 4) 45 = X ^ 2 + 4X X ^ 2 + 4X – 45 = 0 D = 16 + 4 • 45 = 16 + 180 = 196 X1 = (-4 + 16) \ 2 = 6 X2 <0 AB = 6 cm BC = 10 cm
Answer: 6 cm, 10 cm



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