One side of the rectangle is 5 dm and its area is 100 square dm. How many times the width of the rectangle is less than its length.

1) Let us find out how long this rectangle has, if it is known that its area is 100 dm², and its width is 5 dm.

100/5 = 20 dm.

2) Let’s find out how many times the length of the rectangle is greater than its width, if it is known that the width is 5 dm, and we found out its length and it was 20 dm.

20/5 = 4 times.

Answer: The length of the rectangle is 4 times longer than its width.



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