One side of the rectangle is 5cm shorter than the other, and its perimeter is 22cm. Find the area of the rectangle.

Let one of the sides of the rectangle be equal to X cm, AB = X cm, then the length of the other side is equal to (X + 5) cm, BC = (X + 5) cm.

Since AВСD is a rectangle, its perimeter is equal to: Ravsd = 2 * (AB + BC).

22 = 2 * (X + X + 5).

4 * X = 12 cm.

X = AB = СD = 12/4 = 3 cm.

BC = AD = 3 + 5 = 8 cm.

Then the area of the rectangle is: S = AB * BC = 3 * 8 = 24 cm2.

Answer: The area of the rectangle is 24 cm2.



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