One side of the rectangle is equal to 3 whole 1/9 dm, and the other is 61/63 dm less than it.

| September 19, 2021 | education

One side of the rectangle is equal to 3 whole 1/9 dm, and the other is 61/63 dm less than it. Calculate the perimeter and area of the rectangle.

Let’s designate one side of the rectangle A = 3 1/9 dm, the second B = A – 61/63 dm.

It is necessary to calculate the perimeter P and area S of the rectangle.

Let’s find the second side first.

B = 3 1/9 dm – 61/63 dm.

B = 2 dm + 1 1/9 dm – 61/63 dm.

B = 2 dm + 10/9 dm – 61/63 dm.

B = 2 dm + 70/63 dm – 61/63 dm.

B = 2 dm + 9/63 dm.

B = 2 1/7 dm.

Now let’s calculate the perimeter of the rectangle.

P = 2 * (A + B).

P = 2 * (3 1/9 dm + 2 1/7 dm).

P = 2 * (3 dm + 7/63 dm + 2 dm + 9/63 dm).

P = 2 * (5 dm + 16/63 dm).

P = 10 dm + 32/63 dm.

P = 10 32/63 dm.

It remains to calculate the area of ​​the rectangle.

S = A * B.

S = 3 1/9 dm * 2 1/7 dm.

S = 28/9 dm * 15/7 dm.

S = 20/3 dm2.

S = 6 2/3 dm2.

Answer: the perimeter of the rectangle is 10 32/63 dm, the area of ​​the rectangle is 6 2/3 dm2.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.