# One side of the triangle is 3 dm 6 cm long, and the other is twice as long. The length of the third side is 4 dm

**One side of the triangle is 3 dm 6 cm long, and the other is twice as long. The length of the third side is 4 dm 3 cm less than the sum of the lengths of the first two sides. Find the perimeter of the triangle.**

If one of the sides of the triangle has a length of 3 dm 6 cm, and the other is twice as long, then the length of the second side will be 6 dm 12 cm.Now we find the length of the third side, knowing that it is 4 dm 3 cm less than the sum of the lengths of the first two sides (3 dm 6 cm + 6 dm 12 cm – 4 dm 3 cm = 9 dm 18 cm – 4 dm 3 cm = 5 dm 15 cm). Knowing the lengths of all sides of the triangle, we find its perimeter by adding the lengths of their sides: 3 dm 6 cm + 6 dm 12 cm + 5 dm 15 cm = 14 dm 33 cm.

Answer: the perimeter of the rectangle is 14 dm 33 cm.