One side of the triangle is 3m 4dm 8cm, the second 29dm, and the third 4m 2cm. Find the perimeter of the triangle.

Let’s call this triangle ABC,

AB = 3m 4dm 8cm;

BC = 29 dm;

AC = 4m 2cm.

Let’s convert all units of measurement to dm:

1 m = 10 dm,

1 dm = 10 cm, then:

3 m 4 dm 8 cm = 30 dm + 4 dm + 0.8 dm = 34.8 dm,

4 m 2 cm = 40 dm + 0.2 dm = 40.2 dm.

The perimeter is the sum of the lengths of all sides, in this case a triangle.

P = AB + BC + AC;

P = 34.8 dm + 29 dm + 40.2 dm = 104 dm.

Answer: 104 dm.