One side of the triangle is 3m, the second is 50cm less and the third is 8in less than the first two sides

One side of the triangle is 3m, the second is 50cm less and the third is 8in less than the first two sides. Find the perimeter of the triangle.

First, find the length of the second side of the triangle, if it is known that it is 50 cm less than the first:

3 m = 300 cm.

300 – 50 = 250 cm.

Next, you need to find the sum of the lengths of the first two sides:

300 cm + 250 cm = 550 cm.

Now we find out the length of the second side, if it is known that it is less than the first and the second by 8 dm:

8 dm = 80 cm.

550 – 80 = 470 cm.

Let’s define the perimeter of the triangle:

P = a + b + c, where a – 1 side, b – 2 side, c – 3 side.

P = 300 + 250 + 470 = 1020 cm.

Answer: the perimeter of the triangle is 1020 cm.