One side of the triangle is equal to 8 point one-fifths of a cm, the second is 1 point four-fifths of a cm
One side of the triangle is equal to 8 point one-fifths of a cm, the second is 1 point four-fifths of a cm less than the first, and the sum of these sides is 3 point four-fifths of a cm more than the third side.
Find the length of the second side – subtract 1 4/5 from the length of the first side, having previously converted the fractions to the wrong form:
8 1/5 + 1 4/5 = 41/5 + 9/5 = 50/5 = 10 cm
Now let’s find the sum of the two sides:
8 1/5 + 10 = 18 1/5 cm
Find the length of the third side – subtract 3 4/5 from the sum of the two sides:
18 1/5 – 3 4/5 = 90/5 – 19/5 = 71/5 cm
Now we can find the perimeter – add up the lengths of all sides:
8 1/5 + 10 + 71/5 = 41/5 + 50/5 + 71/5 = 162/5 = 32 2/5 cm.
Answer: the perimeter of the triangle is 32 2/5 cm.