One ton of ore is lifted from a mine 60 meters deep using a hoist in 2o seconds. Determine the power of the hoist motor?

univerkov | April 25, 2021 | education

Given: h (shaft depth) = 60 m; m (mass of ore raised) = 1 t (in SI m = 1 * 10 ^ 3 kg); t (duration of ore rise) = 20 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the engine power of the used lift, we use the formula: N = A / t = m * g * h / t.

Calculation: N = 1 * 10 ^ 3 * 10 * 60/20 = 30 * 10 ^ 3 W = 30 kW.

Answer: The motor of the used hoist has a power of 30 kW.

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