One train left city A at 12:00 at a speed of 220 km / h. Another train left city B at 13:00 at a speed of 240 km / h.

One train left city A at 12:00 at a speed of 220 km / h. Another train left city B at 13:00 at a speed of 240 km / h. The length of the path between cities A and B is 1140 km. At what time they will meet.

Given: 220 km / h speed of the first train, 240 km / h speed of the second train, 1140 km distance between points, one train departed at 12.00, and the second at 13.00.

1) 1140 – 220 = 920 km left to go by the first train to point B.

2) 220 + 240 = 460 km passed both trains before the meeting in the first hour,

3) 920 – 460 = 460 km left to go by two trains before the meeting.

4) 12 + 3 = 15 hours and 13 + 2 = 15 hours (since the first train covered 220 km every hour, it will cover 220 * 3 = 660 km before the meeting, and the second left the point an hour later and covered 240 * 2 = 480 km, so they will meet at 15.00).

Answer: trains will meet at 15.00.



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