Oxidation of 4.3 g of aldehyde with an ammonia solution of silver oxide produced 10.8

Oxidation of 4.3 g of aldehyde with an ammonia solution of silver oxide produced 10.8 g of metal. Name the aldehyde, write the corresponding equation.

Let us denote the molar mass of the aldehyde radical by x.

Then the molar mass of the aldehyde will be:

M (RCOH) = x + Ar (C) + Ar (O) + Ar (H) = x + 12 + 16 + 1 = x + 29.

Let us write down the equation of aldehyde oxidation and make up the proportion.

RCOH + Ag2O → RCOOH + 2Ag ↓.

4.3 (2 x 108) = 10.8 (x + 29).

4.3 × 216 = 10.8x + 313.2.

928.8 – 313.2 = 10.8 x.

615.6 = 10.8 x,

x = 615.6: 10.8,

x = 57.

M (RCOH) = 57 + 29 = 86 g / mol.

Н 3С – СН2 – СН2 – СН2СОН (butanal).