Oxygen weighing 5 g occupies a volume of 8.31 liters at a temperature of 47 ° С. What pressure does the gas exert?

M (O2) = 0.032 kg / mol.

m = 5 g = 0.005 kg.

V = 8.31 l = 0.00831 m3.

R = 8.31 m2 * kg / s2 * ° K * mol.

t = 47 ° C.

P -?

Let us write the Mendeleev-Cliperon equation: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal constant, T is the absolute temperature, M is the molar mass of the gas.

P = m * R * T / M * V.

T = t + 273 = 47 ° C + 273 = 320 ° K.

Oxygen is a diatomic gas O2, so we can find its molar mass according to the periodic table: M (O2) = 0.032 kg / mol.

P = 0.005 kg * 8.31 m2 * kg / s2 * ° K * mol * 320 ° K / 0.032 kg / mol * 0.00831 m3 = 50,000 Pa.

Answer: the oxygen pressure is P = 50,000 Pa.