Parallelogram ABCD has diagonal AC = 16cm and diagonal BD = 10cm and side AB = 8cm

Parallelogram ABCD has diagonal AC = 16cm and diagonal BD = 10cm and side AB = 8cm Find the perimeter of triangle COD.

Given:
parallelogram ABCD,
AC and BD are the diagonal of the parallelogram ABCD,
AC = 16 centimeters,
BD = 10 centimeters,
AB = 8 centimeters
AC and BD intersect at point O.
Find the perimeter of a triangle COD -?
Decision:
Consider a parallelogram ABCD. We know that the diagonals in the parallelogram are halved by the intersection point.
Then AO = OS = 16: 2 = 8 (centimeters) and BO = OD = 10: 2 = 5 (centimeters).
In a parallelogram, the opposite angles are equal. Therefore AB = CD = 10: 2 = 5 (centimeters).
The perimeter of the triangle COD, that is, P = 5 + 8 + 8 = 21 (centimeter).
Answer: 21 centimeters.