Performing the Carnot cycle, the gas received heat QН = 1 kJ from the heater and performed work A = 200 J.

Performing the Carnot cycle, the gas received heat QН = 1 kJ from the heater and performed work A = 200 J. Heater temperature ТН = 375 K. Determine the refrigerator temperature

We use the formulas: n (efficiency) = (A \ Qn) * 100%; n (efficiency) = ((Tn-Tx) \ Tn) * 100%
We translate 1kJ = 1000J
n = 200 \ 1000 = 0.2 (20%)
Knowing the efficiency, we can also find the temperature of the refrigerator, making the proportion
0.2 = ((375-x) \ 375)
75 = 375’s
x = 300
Answer: 300