Perimeter 28, find the area of the rectangle if one side is 2cm larger than the other.

1. Let’s take the width of the rectangle as x cm.

2. Since, according to the problem, the length of the rectangle is 2 cm larger than its width, so it will be equal to (x + 2) cm.

3. Let’s make an equation and calculate what the width of this rectangle is equal to if it is known that its perimeter is 28 cm.

x + x + (x + 2) + (x + 2) = 28;

x + x + x + 2 + x + 2 = 28;

4x + 4 = 28;

4x = 28 – 4;

4x = 24;

x = 24/4;

x = 6 cm.

4. Find what is the length of the rectangle.

6 + 2 = 8 cm.

5. Let’s calculate what is the area of the given rectangle.

6 * 8 = 48 cm ^ 2.

Answer: The area of the rectangle is 48 cm ^ 2.