Perimeter 48cm, width 1/2 of the length. Find the lengths of the sides of the rectangle.

| December 29, 2020 | education

By the condition of the problem, the perimeter of the rectangle is 48 cm, that is, the doubled sum of the two sides is 48 cm.Let’s find the sum of the two sides of the rectangle, dividing the perimeter by 2:
48: 2 = 24 (cm).
The sum of the two sides of the rectangle is 24 cm. The width is 1/2 of the length, that is, the width is half the length. Accordingly, the length will be equal to 1.5 parts.
Let’s calculate the length of the rectangle by dividing the sum of the two sides by 1, 5:
24: 1, 5 = 16 (cm) – the length of the rectangle.
Let’s find the width of the rectangle:
16: 2 = 8 (cm) – the width of the rectangle.
Let’s check: P = 2 (16 + 8) = 2 * 24 = 48 (cm).
Answer: the length of the rectangle is 16 cm, the width of the rectangle is 8 cm.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.