Perimeter rectangle 66 in. The length of one side is three equal perimeters. Find an area with a square.

The perimeter of the rectangle is 66 dm.
The length of the side of the rectangle is – 3/11 of the perimeter.
Let’s define the area of this rectangle.
First you need to determine the length of this rectangle.
66: 11 * 3 = 18 dm.
Next, we define the width of this rectangle.
(66 – 18 * 2): 2 = (66 – 36): 2 = 30: 2 = 15 dm.
Next, you need to determine the area of this rectangle.
S = a * b = 18 * 15 = 270 dm ^ 2.
Therefore, the area of this rectangle is 270 dm ^ 2.
Answer: the area is 270 dm ^ 2.