Place the coefficients in the reaction equation and calculate how many liters of carbon dioxide are obtained

Place the coefficients in the reaction equation and calculate how many liters of carbon dioxide are obtained from 25 grams of calcium carbonate. Мr (CaCO3) = 100 CaCO3 + HCl → CaCl2 + CO2 + H2O

Given:
m (CaCO3) = 25 g
Мr (СаСО3) = 100 g / mol

Find:
V (CO2) -?

Solution:
1) Write the reaction equation:
CaCO3 + 2HCl => CaCl2 + CO2 ↑ + H2O;

2) Find the amount of substance CaCO3:
n (CaCO3) = m (CaCO3) / Mr (CaCO3) = 25/100 = 0.25 mol;

3) Find the amount of substance CO2 (taking into account the reaction equation):
n (CO2) = n (CaCO3) = 0.25 mol;

4) Find the volume of CO2:
V (CO2) = n (CO2) * Vm = 0.25 * 22.4 = 5.6 liters.

Answer: The volume of CO2 emitted was 5.6 liters.