Place the odds using the electronic balance method. Indicate the oxidizing agent and the reducing agent, which are the processes of oxidation, reduction. K2MnO4 + Cl2 = KMnO4 + KCl
K2Mn (+6) O4 + Cl (0) 2 = KMn (+7) O4 + KCl (-)
Mn (+6) -e = Mn (+7) | 2 | reducing agent, oxidation
Cl (0) 2 + 2е = 2Cl (-) | 1 | oxidizing agent, reduction
2K2MnO4 + Cl2 = 2KMnO4 + 2KCl
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