Plane a is drawn through the side AC of triangle ABC (angle C = 90 degrees);

Plane a is drawn through the side AC of triangle ABC (angle C = 90 degrees); BB1 perpendicular to a, CB1 perpendicular to AC, AB = 25, AC = 24 Find the area of triangle ABC.

From the right-angled triangle ABC, according to the Pythagorean theorem, it follows that the sum of the squares of the legs is equal to the square of the hypotenuse
Formula: BC = √ (AB² – AC²)

BC = √ (25² – 24²) = √625-576 = √49 = 7
The area of a right-angled triangle is half the product of the legs:
Formula: Sabc = 1/2 * AC * BC

Sabc = 1/2 * 24 * 7 = 84 sq. units