Point A and B lie on opposite sides of a straight line, AM and BK are perpendicular to this straight line

Point A and B lie on opposite sides of a straight line, AM and BK are perpendicular to this straight line. Prove that triangle AMK = triangle ВKM if AK = BM.

Consider triangles AMK and MKВ: common side MK, MВ = KA (hypotenuse by construction), Angle ВKM = angle KMA = 90 ° (since AM and KB are perpendiculars to the straight line MK). The angles ВKM and KMA, MCA and KMВ are wounds in pairs and are crosswise lying. The triangles are equal in side and two corners.



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