Point about the center of a regular triangle ABC, the side of which is 6cm. Line MA is perpendicular to the plane ABC.

Point about the center of a regular triangle ABC, the side of which is 6cm. Line MA is perpendicular to the plane ABC. Find the angle between the straight line MO and the plane ABC if MA = 2cm.

To understand the picture, you need to draw a regular triangle on the sheet and put the pen vertically at point A)
Point O divides the medians of the height of a regular triangle in the ratio of 2k1, starting from the vertex.
Find the height AH = 6 ^ 2-3 ^ 2 = 3√3
Then AO = 2 parts of the height = 2√3
MA is a perpendicular, which means MAO is a right-angled triangle. Find MO = √ (4 + 12) = 4
Through the ratio of the side to the sine, we find the angle
Ratio: MO / sinMAO = MA / sinMOA
4/1 = 2 / sinMOA, hence MOA = 2/4 = 1/2, so the angle is 30 *