Point K is marked on the segment DE. DE = 36cm, DK is 5 times larger than the segment EK. Find

Point K is marked on the segment DE. DE = 36cm, DK is 5 times larger than the segment EK. Find: a) the lengths of the segments DK and EK b) the distance from the middle of the segment DE to the point K.

A) DE = 36, DK is 5p more than KE. Let KE = x, then DK = 5x. x + 5x = 36 -> 6x = 36 -> x = 6cm (KE) DK = 6 × 5 = 30cm.
B) middle DE = 1/2 × 36 = 18cm. Distance to point K 18-KE = 18-6 = 12cm
Answer: 6cm, 30cm, 12cm



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