Point M is the middle of the AC side of the ABC triangle. 1) Construct a segment MB1, on which the AB side

Point M is the middle of the AC side of the ABC triangle. 1) Construct a segment MB1, on which the AB side is displayed with a parallel transfer to the AM vector. 2) Find the perimeter of triangle MDC, where D is the point of intersection of segments BC and MB1, if the perimeter of triangle ABC is 12 m.

Let’s make a parallel transfer of the side AM to point B, the segment AM is parallel to BB1.

The sought segment MB1 is parallel to AB, since AM = BB1 and are parallel.

Point M is the middle of AC, MD is parallel to AB, then MD is the middle line of triangle ABC, then MD = AB / 2, CM = AC / 2, СD = BC / 2.

Rmds = (AB + AC + BC) / 2 = 12/2 = 6 cm.

Answer: The perimeter of the MDС triangle is 6 cm.