Point M lies on rays AB and BA and is equidistant from points A and B. Find the distance from

Point M lies on rays AB and BA and is equidistant from points A and B. Find the distance from M to B if this distance is 8 cm less than the distance from A to B.

Let’s paraphrase the problem into understandable language. There is a segment AB, point M lies on this segment and divides it in half. In this case, AM is 8 cm less than AB. Find MB. Let the distance MB be equal to “x” cm. Then AB is equal to “2x” cm, because AM = MB and AM + MB = AB. Knowing that MB is less than AB by 8 centimeters, we make an equation. 2x – x = 8 x = 8 So MB = x = 8 cm.It turns out AB = 2x = 16 cm.2x = 2 * 8 = 16
Answer: the distance MB is 8 centimeters.