Points A (-2; 5), B (4; 3), C (4; 7) are marked on the plane. Find the length of the vector AB-AC.

The solution of the problem:
Vector AB = {4 – (- 2); 3 – 5} = {6; – 2}.
Vector AC = {4 – (- 2); 7 – 5} = {6; 2}.
Then (AB – AC) = {6 – 6; – 2 – 2} = {0; – 4}.
Find the length of the resulting vector:
| AB – AC | = √ (0 ^ 2 + (- 4) ^ 2) = √ (16) = 4.
Answer: | AB – AC | = 4.



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