Points A and B were marked on a circle with a diameter of 18 cm so that from these points and the center

Points A and B were marked on a circle with a diameter of 18 cm so that from these points and the center of the circle O an equilateral triangle was obtained. How much is the perimeter of triangle OAB?

Let us construct a triangle with vertices in the center of the circle and on the circle itself by the condition of the problem.

We see that the two sides of the resulting triangle are the radii of a given circle, the diameter of which is 18 cm.

It is known that the constructed triangle is equilateral.

This means that the lengths of all three sides correspond to the radius of the circle.

We calculate the value of each side of the triangle as half the diameter d of the circle.

d / 2 = 18 cm: 2 = 9 cm.

Answer: The sides of a triangle are 9 centimeters long.



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