Points A, B, C, D, E, F are located on one straight line in the specified order. We know AF = 35

univerkov | September 8, 2021 | education

Points A, B, C, D, E, F are located on one straight line in the specified order. We know AF = 35, AC = 12, BD = 11, CE = 12, DF = 16. Find BE.

It is known that points A, B, C, D, E, F are located on one straight line in the indicated order, which means that A is the beginning of the segment, F is the end of the segment and its length AF = 35 is known. To find the segment EF, it is necessary to subtract the segment AE from the segment AF. AE = AC + CE. AE = 12 + 12 = 24.
EF = AF – AE = 35 – 24 = 11.
DE = DF – EF; DE = 16 – 11 = 5.
In order to find the segment BE, it is necessary to add the segments BD and DE. The segment BD is known by the problem statement; its length is BD = 11.
BE = BD + DE; BE = 11 + 5 = 16.
Answer: BE = 16.

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