Points B and D lie in different half-planes relative to line AC. Triangles ABC and ADC are isosceles rectangular

Points B and D lie in different half-planes relative to line AC. Triangles ABC and ADC are isosceles rectangular (angle B = angle D = 90 degrees) Prove that AB || CD.

triangle ABC = triangle ADC – by 3 signs (AB = AD and BC = DC- by condition, and AC common) AB and CD straight lines AC – secant => angle BAC = angle ACD – intersecting => AB || CD



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