Points M and N are taken on the circle on opposite sides of the diameter AB. It is known that ∠NBA = 68 °.

Points M and N are taken on the circle on opposite sides of the diameter AB. It is known that ∠NBA = 68 °. Find the corner NMB.

Consider a triangle ABN.

Since AB is the diameter, triangle ABN is right-angled with right angle ANB.

According to the problem statement, the angle ∠NBA = 68 °.

Then ∠NAB = 180 ° – ∠ANB – ∠NBA = 180 ° – 90 ° – 68 ° = 22 °.

Note that the angles ∠NAB and ∠NMB rest on the same arc NB,

therefore they are equal.

Therefore, ∠NMB = 22 °.



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