Potassium hydroxide + copper sulfate (2) Write in ionic form.

Let’s write down the formulas of the compounds: potassium hydroxide – KOH (alkali), copper (II) sulfate – CuSO4 (salt).
Salts react with bases to form a weak electrolyte (in this case, an insoluble base Cu (OH) 2). Let’s write the molecular form of the equation:
2KOH + CuSO4 = Cu (OH) 2 + K2SO4
Let us write the equation in full ionic form:
2K (+) + 2OH (-) + Cu (2+) + SO4 (2-) = Cu (OH) 2 + 2K (+) + SO4 (2-)
Let’s reduce the repeated ions in products and reagents and get the shortened ionic equation:
Cu (2+) + 2OH (-) = Cu (OH) 2